Talk:Dwarvish Dice: Difference between revisions

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This will take some time :)
This will take some time :)
* More details. Here's hopw you can go about figurign this out (I think).
Them = D,F
Me  = D,A
Result Gain 7
7/7 = 1
DA - DF = 1
Therefore (A – F = 1)
Them = H,A
Me  = H,G
Result Lose 42
-42/7 = -6
HG - HA = -6
Therefore (G – A = -6)
Not impossible, just takes some time :).--[[User:Quickdart|Quickdart]] 22:51, 27 April 2009 (UTC)


*I had a rather lengthy post written up because I hadn't found the Language discussion... thanks for the help.  I can confirm the role of the x7 as mentioned above for my 25 rolls, for what that is worth. --[[User:Miststlkr|Miststlkr]] 21:43, 27 April 2009 (UTC)
*I had a rather lengthy post written up because I hadn't found the Language discussion... thanks for the help.  I can confirm the role of the x7 as mentioned above for my 25 rolls, for what that is worth. --[[User:Miststlkr|Miststlkr]] 21:43, 27 April 2009 (UTC)

Revision as of 22:51, 27 April 2009

Seems as two random rune digits are thrown for each player, then the difference is calculated, and multiplied by 7. The values of the digits? I'm on it. Sure about the *7 part, though, 'cause 40/40 results are dividable through 7. --Ocoma 21:29, 27 April 2009 (UTC)



Some results from my testing. Value of the digits can be found at Dwarvish language.--Quickdart 21:31, 27 April 2009 (UTC)

  • OK heard the possibility of this being base 7. How does that make things work...

B + B = 1,1 = 1 * 7 + 1 * 1 = 8

D + D = 3,3 = 3 * 7 + 3 * 1 = 24

diff = 24 - 8 = 16

Gain = 56 = 16 * 3.5


F + B = 6,1 = 6* 7 + 1*1 = 43

B + B = 1,1 = 1 * 7 + 1 * 1 = 8

diff = 43 - 8 = 35

Lose = 196 = 35 * 5.6

... not quite.... B + B = 2,2 = 2 * 7 + 2 * 1 = 16

D + D = 4,4 = 4 * 7 + 4 * 1 = 32

diff = 32 - 16 = 16

Gain = 56 = 16 * 3.5

F + B = 7,2 = 7 * 7 + 2 * 1 = 51

B + B = 2,2 = 2 * 7 + 2 * 1 = 16

diff = 51 - 16 = 35

Lose = 196 = 35 * 5.6

Gah! --Quickdart 22:33, 27 April 2009 (UTC)

  • OK scrapping my results. From what I can see, yes the result is multiplied by 7, but the name of the rune isn't necessarily congruent with it's value. Ex new rolls

Them D F

Me D A

Result +7

Therefor DA - DF = 1 , A - F = 1


Them H A

Me H G

Result -42

Therefore HG - HA = -42 , G - A = -7

This will take some time :)

  • More details. Here's hopw you can go about figurign this out (I think).

Them = D,F

Me = D,A

Result Gain 7

7/7 = 1

DA - DF = 1

Therefore (A – F = 1)

Them = H,A

Me = H,G

Result Lose 42

-42/7 = -6

HG - HA = -6

Therefore (G – A = -6)

Not impossible, just takes some time :).--Quickdart 22:51, 27 April 2009 (UTC)


  • I had a rather lengthy post written up because I hadn't found the Language discussion... thanks for the help. I can confirm the role of the x7 as mentioned above for my 25 rolls, for what that is worth. --Miststlkr 21:43, 27 April 2009 (UTC)

Yeah--this is how you decode the digits. However, I was getting different values for them, I think. The main thing to remember is that the Dwarven digits are BASE SEVEN! That means no rune can represent 7 (just like in our base 10, no digit can represent 10; we use two).Qaianna 21:47, 27 April 2009 (UTC)

That's not a well founded assumption when looking at dice. a d10 has numbers 1-10, a d8 1-8, and so on. Why says that a d7 doesn't have 1-7 as opposed to 0-6?--Valliant 22:08, 27 April 2009 (UTC)

Something to note: The number on the dice is set up as the first die being the sevens digit and the second die being the ones digit, or vice versa. That is, they can't be the same value. When the dwarf rolled H,C, and I rolled C,H, I won 126 meat, which means that the sequence in which the numbers come is important. --Valliant 22:12, 27 April 2009 (UTC)