Talk:Dwarvish Dice

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Revision as of 21:44, 27 April 2009 by imported>Miststlkr

Seems as two random rune digits are thrown for each player, then the difference is calculated, and multiplied by 7. The values of the digits? I'm on it. Sure about the *7 part, though, 'cause 40/40 results are dividable through 7. --Ocoma 21:29, 27 April 2009 (UTC)



Some results from my testing. Value of the digits can be found at Dwarvish language.--Quickdart 21:31, 27 April 2009 (UTC)

B + B = 1 + 1 , 11

D + D = 3 + 3 , 33

diff = 4 , 22

Gain = 56


F + B = 6 + 1, 61

B + B = 1 + 1, 11

diff = 5 , 50

Lose = 196


B + H = 1 + 7, 17

D + A = 3 + 0, 30

diff = 5 , 13

Gain = 63


B + H = 1 + 7, 17

A + H = 0 + 7, 07

diff = -1, -7

Gain = 245

A + G= 0 + 6, 06

E + F= 4 + 5, 45

diff = 3, 39

Lose = 112


  • I had a rather lengthy post written up because I hadn't found the Language discussion... thanks for the help. I can confirm the role of the x7 as mentioned above for my 25 rolls, for what that is worth. --Miststlkr 21:43, 27 April 2009 (UTC)