Talk:Dwarvish Dice

Seems as two random rune digits are thrown for each player, then the difference is calculated, and multiplied by 7. The values of the digits? I'm on it. Sure about the *7 part, though, 'cause 40/40 results are dividable through 7. --Ocoma 21:29, 27 April 2009 (UTC)

Some results from my testing. Value of the digits can be found at Dwarvish language.--Quickdart 21:31, 27 April 2009 (UTC)

B + B = 1 + 1 , 11

D + D = 3 + 3 , 33

diff = 4 , 22

Gain = 56

F + B = 6 + 1, 61

B + B = 1 + 1, 11

diff = 5 , 50

Lose = 196

B + H = 1 + 7, 17

D + A = 3 + 0, 30

diff = 5 , 13

Gain = 63

B + H = 1 + 7, 17

A + H = 0 + 7, 07

diff = -1, -7

Gain = 245

A + G= 0 + 6, 06

E + F= 4 + 5, 45

diff = 3, 39

Lose = 112

• I had a rather lengthy post written up because I hadn't found the Language discussion... thanks for the help. I can confirm the role of the x7 as mentioned above for my 25 rolls, for what that is worth. --Miststlkr 21:43, 27 April 2009 (UTC)

Yeah--this is how you decode the digits. However, I was getting different values for them, I think. The main thing to remember is that the Dwarven digits are BASE SEVEN! That means no rune can represent 7 (just like in our base 10, no digit can represent 10; we use two).Qaianna 21:47, 27 April 2009 (UTC)

That's not a well founded assumption when looking at dice. a d10 has numbers 1-10, a d8 1-8, and so on. Why says that a d7 doesn't have 1-7 as opposed to 0-6?--Valliant 22:08, 27 April 2009 (UTC)