Talk:Dwarvish Dice
Seems as two random rune digits are thrown for each player, then the difference is calculated, and multiplied by 7. The values of the digits? I'm on it. Sure about the *7 part, though, 'cause 40/40 results are dividable through 7. --Ocoma 21:29, 27 April 2009 (UTC)
Some results from my testing. Value of the digits can be found at Dwarvish language.--Quickdart 21:31, 27 April 2009 (UTC)
- OK heard the possibility of this being base 7. How does that make things work...
B + B = 1,1 = 1 * 7 + 1 * 1 = 8
D + D = 3,3 = 3 * 7 + 3 * 1 = 24
diff = 24 - 8 = 16
Gain = 56 = 16 * 3.5
F + B = 6,1 = 6* 7 + 1*1 = 43
B + B = 1,1 = 1 * 7 + 1 * 1 = 8
diff = 43 - 8 = 35
Lose = 196 = 35 * 5.6
... not quite.... B + B = 2,2 = 2 * 7 + 2 * 1 = 16
D + D = 4,4 = 4 * 7 + 4 * 1 = 32
diff = 32 - 16 = 16
Gain = 56 = 16 * 3.5
F + B = 7,2 = 7 * 7 + 2 * 1 = 51
B + B = 2,2 = 2 * 7 + 2 * 1 = 16
diff = 51 - 16 = 35
Lose = 196 = 35 * 5.6
Gah! --Quickdart 22:33, 27 April 2009 (UTC)
- OK scrapping my results. From what I can see, yes the result is multiplied by 7, but the name of the rune isn't necessarily congruent with it's value. Ex new rolls
Them D F
Me D A
Result +7
Therefor DA - DF = 1 , A - F = 1
Them H A
Me H G
Result -42
Therefore HG - HA = -42 , G - A = -7
This will take some time :)
- More details. Here's hopw you can go about figurign this out (I think).
Them = D,F
Me = D,A
Result Gain 7
7/7 = 1
DA - DF = 1
Therefore (A – F = 1)
Them = H,A
Me = H,G
Result Lose 42
-42/7 = -6
HG - HA = -6
Therefore (G – A = -6)
Not impossible, just takes some time :).--Quickdart 22:51, 27 April 2009 (UTC)
- I had a rather lengthy post written up because I hadn't found the Language discussion... thanks for the help. I can confirm the role of the x7 as mentioned above for my 25 rolls, for what that is worth. --Miststlkr 21:43, 27 April 2009 (UTC)
Yeah--this is how you decode the digits. However, I was getting different values for them, I think. The main thing to remember is that the Dwarven digits are BASE SEVEN! That means no rune can represent 7 (just like in our base 10, no digit can represent 10; we use two).Qaianna 21:47, 27 April 2009 (UTC)
- That's not a well founded assumption when looking at dice. a d10 has numbers 1-10, a d8 1-8, and so on. Why says that a d7 doesn't have 1-7 as opposed to 0-6?--Valliant 22:08, 27 April 2009 (UTC)
Something to note: The number on the dice is set up as the first die being the sevens digit and the second die being the ones digit, or vice versa. That is, they can't be the same value. When the dwarf rolled H,C, and I rolled C,H, I won 126 meat, which means that the sequence in which the numbers come is important. --Valliant 22:12, 27 April 2009 (UTC)
After more than 30 trials, I'm satisfied with the conclusion that the Dwarven number system is base seven, that the dice are numbered 0-6, and that the order matters, in that together a roll represents a two-digit number in base seven. Also, double-zeroes as a roll counts as 100 in base seven, or rather a roll of 49, so payout is 7*(49-(value of the other roll)). TimRem 22:55, 27 April 2009 (UTC)
As far as I can tell the rules are as follows:
7 out of the ten possible runes in Dwarvish language are used, presumably randomised for the player. Each rune represents a digit from 0 to 6, the order of the dice is significant, one dice role therefore represents a number from 00 to 66 in base 7. The payout is the difference between the higher roll and the lower roll multiplied by 7, paid from the lower roll to the higher. Anyone want to confirm? --Atillo 22:49, 27 April 2009 (UTC)
Confirmed. On my account there are 7 of these runes, and after playing the dice game many times and taking tedious notes, I am now able to predict perfectly what I will owe/win. It is indeed 7 times the decimal difference between the two numbers.--Krazybob 23:07, 27 April 2009 (UTC)
One very convenient way to think of the payoff is (using the base 7 method) that the first roll is the "49"s place and the second is the "7"s place... and the "1"s place is zero. However, I had not rolled a double zero in my trial, so that needs to be taken into account. --Almightysapling 00:46, 28 April 2009 (UTC)
Its 7 of the 7 values of the Dwarvish Numerical System, and there are actually 12 letters i believe, and do you mean (higher- lower)*7 cause that would make sense, but we really only need to know the values. Also my friend had the same Dwarven letters for the other thing but didnt checkc the digits, so i think it might be universal--Coolness 23:10, 27 April 2009 (UTC)
The alphabet and numbers are different for each player. My clan tested that. Also, I would have to disagree that one is the 10's place, and 1 is the 1's place, unless that somehow means that the first digit doesn't determine which number is higher, because my testing has disproven that assumption.--Terrabull 01:05, 29 April 2009 (UTC)- Also, when I roll what I assume to be two zeros, it always loses.--Terrabull 01:07, 29 April 2009 (UTC)
My new theory is that this is a 2-die poker game. Highest hand wins, left number breaks ties.--Terrabull 01:34, 29 April 2009 (UTC)
- Never mind, apparently one of my proofs go copied wrong.--Terrabull 02:11, 29 April 2009 (UTC)
